证明:∵∠B+∠BAD=∠1+∠EDC,
又∵∠B=∠1,
∴∠BAD=∠EDC.
又AB=AC,
∴∠B=∠C.
又AD=DE,
∴ADB≌△DEC.
如图,在△ABC中,AB=AC,D、E分别在BC、AC边上,且∠1=∠B,AD=DE, 求证:△ADB≌△DEC.
如图,在△ABC中,AB=AC,D、E分别在BC、AC边上,且∠1=∠B,AD=DE,
求证:△ADB≌△DEC.
求证:△ADB≌△DEC.
数学人气:352 ℃时间:2019-12-12 22:19:18
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