已知x=2-根号3,求（x-1分之1-2x+x平方）-（x平方-x 分之根号x平方-2x+1）的值.

x=2-√3x-1=1-√3﹤0原式=(1-2x+x²)/(x-1)-√(x²-2x+1)/(x²-x)=(x-1)²/(x-1)-√(x-1)²/[x(x-1)]=x-1-|x-1|/[x(x-1)]=x-1+(x-1)/[x(x-1)]=x-1+(1/x)=1-√3+1/(2-√3)=1-√3+(2+√3)/[(2+√3...