已知函数f(x)=5sinxcosx-5√3cos^2x+[(5√3)/2] (x∈R)求：函数最小正周期和单调区间

解；依题意得y=(5/2)sin2x-(5√3/2)cos2x=(5/2)sin(π-2x)+(5√3/2)cos(π-2x)=5sin(π-2x+a)tana=(5√3/2)/(5/2)=√3a=π/3y=5sin(π-2x+a)=5sin(π-2x+π/3)=5sin(2x-π/3)y=sinx的单调递增区间是2kπ-π/2...