化简cosπ/9*cos2π/9*cos3π/9*cos4π/9

化简cosπ/9*cos2π/9*cos3π/9*cos4π/9
数学人气:894 ℃时间:2020-03-17 08:42:09
优质解答
k/k法
cosπ/9*cos2π/9*cos3π/9*cos4π/9
=[(2sinπ/9 cosπ/9)*cos2π/9*cos3π/9*cos4π/9]/(2sinπ/9 )
=[(2sin2π/9 cos2π/9)*cos3π/9*cos4π/9]/(4sinπ/9 )
=[(2sin4π/9 cos4π/9)*cos3π/9]/(8sinπ/9 )
=(sin8π/9 cos3π/9)/(8sinπ/9 )
=(cosπ/3)/8
=1/16.
我来回答
类似推荐
请使用1024x768 IE6.0或更高版本浏览器浏览本站点,以保证最佳阅读效果。本页提供作业小助手,一起搜作业以及作业好帮手最新版!
版权所有 CopyRight © 2012-2024 作业小助手 All Rights Reserved. 手机版