[(x+y)²-(x-y)²-2y(x-y)]÷5y
=[X²+2XY+Y²-X²+2XY-Y²-2XY+2Y²]÷5Y
=[2Y(X+Y)]÷5Y
=2/5(X+Y)
=2/5(10)
=4
已知x+y=10,求[(x+y)^2-(x-y)^2-2y(x-y)]÷5y的值
已知x+y=10,求[(x+y)^2-(x-y)^2-2y(x-y)]÷5y的值
数学人气:361 ℃时间:2020-04-16 10:18:55
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