∵点B(4,2)在函数y=2x+b的图象上,
∴2×4+b=2,解得b=-6,
∴该一次函数的解析式为:y=2x-6,
当x=-2时,y=2×(-2)-6=-10≠3,
∴此点不在该函数的图象上.
已知点B(4,2)在函数y=2x+b的图象上,试判断点C(-2,3)是否在该函数的图象上.
已知点B(4,2)在函数y=2x+b的图象上,试判断点C(-2,3)是否在该函数的图象上.
数学人气:612 ℃时间:2020-01-26 05:51:58
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