有一列数:1,2006,2005,1,2004,2003,从第3个数起每一个数都是他前面两个数中大,球从第一个起到2006个数这2006个数之和.
有一列数:1,2006,2005,1,2004,2003,从第3个数起每一个数都是他前面两个数中大,球从第一个起到2006个数这2006个数之和.
数学人气:739 ℃时间:2019-09-27 11:22:23
优质解答
2006/3=668...2 1*(668+1)+[2006+(2006-2*668)]*(2*668+1)/2=1789575
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