原式=[a/(a²-b²)-1/(a+b)]÷[b/(b-a)]
=[a/(a²-b²)-(a-b)/(a²-b²)]×[-(a-b)/b]
=[(a-a+b)/(a²-b²)]×[-(a-b)/b]
={ b/[(a-b)(a+b)] }×[-(a-b)/b]
=-1/(a+b)
计算(a^2-b^2分之a-a+b分之1)\b-a分之b
计算(a^2-b^2分之a-a+b分之1)\b-a分之b
数学人气:784 ℃时间:2020-02-06 01:33:38
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