求满足x-1的立方根+1=x的x值和x+根号下x-3=3的x的值

1.x-1的立方根+1=x的x值
变形为:x-1的立方根=x-1
x-1=x-1的立方
(x-1)((x-1)平方-1)=0
(x-1)x(x-2)=0
x1=0,x2=1,x3=2
2.求x+根号下x-3=3的x的值
变为:根号下x-3=3-x
x-3>=0得x>=3
3-x>=0得x<=3
x=3