第一题 (2x+1)(3x-5)=(2x+1)(x+7) 第二题 25(2a+b)²=9(3a-b)² 解方程

(2x+1)(3x-5)=(2x+1)(x+7) 6x²-7x-5=2x²-15x+74x²+8x-12=0x²+2x-3=0(x+3)(x-1)=0x+3=0 x-1=0x1=-3x2=125(2a+b)²=9(3a-b)²25(2a+b)²-9(3a-b)²=0(10a+5b-9a+3b)(10a+5b+9a-3b...