设第一堆x吨,第二堆(5.7-x)吨
(1-4分之3)x+(1-5分之3)(5.7-x)=x(1-5分之1)
0.25x+0.4(5.7-x)=0.8x
0.25x+2.28-0.4x=0.8x
0.8x+0.4x-0.25x=2.28
0.95x=2.28
x=2.4
答:第一堆有2.4吨.
两堆黄沙共5.7吨,第一堆用去四分之三,第二堆用去五分之三,把两堆剩下的合在一起,比原来第一堆
两堆黄沙共5.7吨,第一堆用去四分之三,第二堆用去五分之三,把两堆剩下的合在一起,比原来第一堆
少五分之一,原来第一堆有多少黄沙?
少五分之一,原来第一堆有多少黄沙?
数学人气:954 ℃时间:2019-12-20 10:07:11
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