用反表示法求函数y=(x-1)/(x+2)(x≥-1)的值域
∵y=(x-1)/(x+2)
∴y(x+2)= x-1
故:yx+2y=x-1
故:yx-x=-1-2y
故:x(y-1)= -1-2y
故:x=(-1-2y)/ (y-1)
∵x≥-1
故:(-1-2y)/ (y-1)≥-1
故:(-1-2y)/ (y-1)+1≥0
故:-(y+2)/ (y-1)≥0
故:(y+2)/ (y-1)≤0
故:-2≤y≤1
用反表示法求函数y=x-1/x+2(x>= -1)的值域
用反表示法求函数y=x-1/x+2(x>= -1)的值域
数学人气:888 ℃时间:2019-12-19 10:20:39
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