(x-1)(2-kx)=-kx2+(2+k)x-2,
∵不含一次项,
∴2+k=0,
解得k=-2.
故答案为:-2.
当k=_时,多项式x-1与2-kx的乘积不含一次项.
当k=______时,多项式x-1与2-kx的乘积不含一次项.
数学人气:739 ℃时间:2019-09-29 07:45:46
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