x<-3
|x+3|+|x-2|
= -(x+3)-(x-2)
= -2x -1
<7
==>
x>-4
==>
-4
|x+3|+|x-2|
=(x+3)-(x-2)
=5
<7
符合,所以,
-3<=x<=2
2
=x+3+x-2
=2x+1
<7
==>
x<3
==>
2
-4
数学题︳x+3︳+︳x-2︳﹤7 求x的取值范围
数学题︳x+3︳+︳x-2︳﹤7 求x的取值范围
数学人气：540 ℃时间：2020-04-14 04:49:26
优质解答
分区间讨论
x<-3
|x+3|+|x-2|
= -(x+3)-(x-2)
= -2x -1
<7
==>
x>-4
==>
-4
|x+3|+|x-2|
=(x+3)-(x-2)
=5
<7
符合,所以,
-3<=x<=2
2
=x+3+x-2
=2x+1
<7
==>
x<3
==>
2
-4
x<-3
|x+3|+|x-2|
= -(x+3)-(x-2)
= -2x -1
<7
==>
x>-4
==>
-4
|x+3|+|x-2|
=(x+3)-(x-2)
=5
<7
符合,所以,
-3<=x<=2
2
=x+3+x-2
=2x+1
<7
==>
x<3
==>
2
-4
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