(x-1)(x+1)=x²-1
(x-1)(x+1)=x²-1
(x-1)(x²+x+1)=x³-1
(x-1)(x³+x²+x+1)=x的四次方-1
(x-1)(x的四次方+x³+x²+x+1)=x的五次方-1
根据前面各式的规律可得:
(x-1)(x的n次方+x的n次方-1+x的n次方-2…+x+1)= (其中n为正整数)
(x-1)(x²+x+1)=x³-1
(x-1)(x³+x²+x+1)=x的四次方-1
(x-1)(x的四次方+x³+x²+x+1)=x的五次方-1
根据前面各式的规律可得:
(x-1)(x的n次方+x的n次方-1+x的n次方-2…+x+1)= (其中n为正整数)
数学人气:427 ℃时间:2020-04-07 18:24:15
优质解答
(x-1)(x的n次方+x的n次方-1+x的n次方-2…+x+1)= X的n+1次方-1
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