若(X的三次方)-6(X的两次方)+11X-6=(X-1)(X的两次方+MX+N),求m的二次方+6mn+9倍的n的平方的值.

x^3-6x^2+11x-6
=x^3-6x+5x+6x-6
=x(x^2-6x+5)+6(x-1)
=x(x-1)(x-5)+6(x-1)
=(x-1)[x(x-5)+6]
=(x-1)(x^2-5x+6)
=(X-1)(X的两次方+MX+N),
M=-5
N=6
m的二次方+6mn+9倍的n的平方=(m+3n)^2=169