(根号3tan12度-3)/(sin12度(4cos^212度-2))
(根号3tan12度-3)/(sin12度(4cos^212度-2))
数学人气:202 ℃时间:2020-01-29 21:28:35
优质解答
原式=(√3sin12/cos12-3)/2sin12*cos24=[√3(sin12-√3cos12)]/sin24*cos24=2√3*2(1/2sin12-√3/2cos12)/sin48=4√3sin(12-60)/sin48=-4√3
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