已知函数f(x)=A\2-A\2cos(2wx+2φ)(A大于0,w大于0,0《φ《π\2)
已知函数f(x)=A\2-A\2cos(2wx+2φ)(A大于0,w大于0,0《φ《π\2)
且y=f(x)的最大值为2,其图像相邻两对称轴间的距离为2,并过点(1,2)1·求φ2·计算 f(1)+f(2)+``````f(2008)
且y=f(x)的最大值为2,其图像相邻两对称轴间的距离为2,并过点(1,2)1·求φ2·计算 f(1)+f(2)+``````f(2008)
数学人气:620 ℃时间:2019-10-24 10:50:52
优质解答
y=f(x)的最大值为2故A/2+A/2=2 得A=2其图像相邻两对称轴间的距离为2故最小正周期T=4即2π/(2w)=4得w=π/4故f(x)=1-cos(π/2x+2ψ)带入点(1,2)得cos(π/2+2ψ)=-1又0≤ψ≤π/2得ψ=π/4 f(1)=2f(2)=1-cos(π+π/2)=1f(3)=1-cos(3π/2+π/2)=0f(4)=1-cos(2π+π/2)=1故f(1)+f(2)+f(3)+f(4)=4故f(1)+f(2)+``````f(2008)=502[f(1)+f(2)+f(3)+f(4)]=2008
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