det(a1+b1,a2+a2,a3+b3,a4+b4)
=det(a1,a2+a2,a3+b3,a4+b4)+det(b1,a2+a2,a3+b3,a4+b4)
=8det(a1,a2,a3,a4)+8det(b1,a2,a3,a4)
=24-40
=-16
行列式|A+B|怎么求?
行列式|A+B|怎么求?
设4阶行列式|A|=det(a1,a2,a3,a4)=3,|B|=det(b1,a2,a3,a4)=-5,求|A+B|
设4阶行列式|A|=det(a1,a2,a3,a4)=3,|B|=det(b1,a2,a3,a4)=-5,求|A+B|
数学人气:691 ℃时间:2020-01-29 05:50:11
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