已知复数z满足:|z|=1+3i-z,求(1+i)2(3+4i)2z的值.
数学人气:769 ℃时间:2020-03-28 02:10:41
优质解答
设z=a+bi(a,b∈R),
而|z|=1+3i-z,即
−1−3i+a+bi=0,
则
,解得
,
z=-4+3i,
∴
=
==1.
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