由已知得√a+√3=√(ab+1),两边平方
a+2√(3a)+3=ab+1
由1/a+1/2b=1/2,得2b+a=ab,代入上式
整理得√(3a)+1=b,即√(3a)=b-1,故
3ab-3b-b²-√(3a)
=3(2b+a)-3b-b²-(b-1)
=-b²+2b+1+3a
=-(b-1)²+3a+2
=2
已知实数a,b满足√a+√3-√(ab+1)=0,且1/a+1/2b=1/2,求代数式3ab-3b-b^2-√3a的值
已知实数a,b满足√a+√3-√(ab+1)=0,且1/a+1/2b=1/2,求代数式3ab-3b-b^2-√3a的值
数学人气:237 ℃时间:2019-10-19 21:52:27
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