方程有两个根,所以a≠0;
因为x1,x2互为相反数,所以x1+x2=-b/a=0且a≠0,所以b=0.
因为x1,x2互为相反数,所以x1*x2=c/a<=0.如果c=0,则两个根相等,舍去.所以x1*x2=c/a<0,c与a异号,则ac<0
若方程ax^2+bx+c=0的两个根互为相反数,求证a≠0,b=0,ac<0
若方程ax^2+bx+c=0的两个根互为相反数,求证a≠0,b=0,ac<0
其他人气:554 ℃时间:2019-12-16 11:01:06
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