原式=(x+1)(x-1)/(x-1)²*(x-1)/x(x+1)+2/x
=(x+1)/(x-1)*(x-1)/x(x+1)+2/x
=1/x+2/x
=3/x
化简【(x的平方-2x+1)分之x的平方-1】乘以【(x的平方+x)分之(x-1)】+(x分之2)
化简【(x的平方-2x+1)分之x的平方-1】乘以【(x的平方+x)分之(x-1)】+(x分之2)
数学人气:726 ℃时间:2019-12-15 05:31:58
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