原式=lim(x->0)(arctanx/tanx)
=lim(x->0){[1/(1+x²)]/sec²x} (0/0型,应用罗比达法则)
=lim(x->0)[1/(1+x²)]*lim(x->0)(cos²x)
=1*1
=1
猜你喜欢
- 1谁能给我详细的介绍下平行板电容器的公式.
- 2形容一个人受到惊吓后动作的四字成语有哪些?
- 3《西江月·夜行黄沙道中》全诗表达了诗人什么的思想感情?
- 4松树的棵树的十分之七相当于柏树的棵数”是把（ ）看作单位“1”,也就是（）的棵树×10分之7＝（）的棵树
- 5I'd like a large bowl of mutton nodles.对划线部分提问.(画的是a large)____ ___buwl of mutton noodl
- 6The Roman people originally lived in northwest India in ＿is now southeastern Pakistan .A .what B .which .C that .D where
- 7两堆苹果.甲堆是乙堆的4/5.甲卖出20千克,乙卖出30千克.这时甲是乙的5/6.乙原有苹果多少千克
- 8在三角形ABC中 AB=AC=3 BC=2 ∠ABC的平分线交BC的平行线于D 求三角形ABD的面积
- 9--- Why not ________ for help when you were in trouble?--- Next time,I will
- 10小学数学单元小结怎么写?