如图a.b是反比例函数y=k/x上两点,ac垂直于y轴于c,bd垂直于x轴于d,ac=bd=4/1oc,四边形abcd的面积=14,则

设 OC=m ,则A点的坐标为(1/4m,m),由于A点在反比例函数上,有
1/4m × m = k ,即 k = 1/4m²
同理可得B点坐标为 (m,1/4m),延长CA,BD交于E点,则有
S(四边形ABCD)
= S(□CODE) - S△COD - S△ABE
= m² - 1/2m² - 1/2(m-1/4m)²
= 7/32m²
= 7/8k
∴ 14 = 7/8k ,得 k = 16