∫（上标3,下标1）x/6dx+∫（上标7/2,下标3)dx=等于多少.

∫(1-->3) x/6 dx + ∫(3-->7/2) dx
= 1/6 · x²/2|(1-->3) + x|(3-->7/2) b) f(x) dx = F(b) - F(a)
= 1/12 · (3² - 1²) + (7/2 - 3)
= 2/3 + 1/2
= 7/6