(1)-2x2y(3xy2z-2y2z); (2)(2ab)2•(a2-b2)-(2a2b2)2÷(4b2)+4a2b4; (3)1232-124×122; (4)(x/2-y)2-1/4(x2-y2); (5)[(2a+b)2-b(b+4
(1)-2x2y(3xy2z-2y2z);
(2)(2ab)2•(a2-b2)-(2a2b2)2÷(4b2)+4a2b4;
(3)1232-124×122;
(4)(
-y)2-
(x2-y2);
(5)[(2a+b)2-b(b+4a)-8a]÷(-
a).
(2)(2ab)2•(a2-b2)-(2a2b2)2÷(4b2)+4a2b4;
(3)1232-124×122;
(4)(
x |
2 |
1 |
4 |
(5)[(2a+b)2-b(b+4a)-8a]÷(-
1 |
2 |
数学人气:392 ℃时间:2020-01-28 12:11:26
优质解答
(1)原式=-6x3y3z+4x2y3z;(2)原式=4a4b2-4a2b4-4a4b4÷4b2+4a2b4=3a4b2;(3)原式=1232-(123+1)×(123-1)=1232-(1232-1)=1232-1232+1=1;(4)原式=14x2-xy+y2-14x2+14y2=-xy+54y2;(5)原式=(4a2+4ab+...
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