由x-√xy-2y=0可知,（√x+√y）（√x-2√y）=0
解得√x=2√y,即x=4y
则（2x-√xy）/(y+2√xy)=(2x-2y)/(y+4y)=6/5
已知 X大于0,Y大于0,且X-根号XY-2Y=0,求2X-根号XY除以Y+2根号XY的值
已知 X大于0,Y大于0,且X-根号XY-2Y=0,求2X-根号XY除以Y+2根号XY的值
数学人气：177 ℃时间：2019-10-02 20:32:46
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