x+y-1的绝对值+(x-y+3)²=0
所以
x+y-1=0
x-y+3=0
所以
x+y=1
x-y=-3
所以x²-y²
=(x+y)(x-y)
=1×(-3)
=-3
我要出去一下了,大概七点三刻左右再上
x+y-1的绝对值+(x-y+3)²=0,则x²-y²=
x+y-1的绝对值+(x-y+3)²=0,则x²-y²=
数学人气:623 ℃时间:2020-01-31 17:57:18
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