(2X-3Y-2XY)-(X-4Y+XY)
=2X-3Y-2XY-X+4Y-XY
=X+Y-3XY
因为x加y等于110,xy等于33
所以原式等于:110-33*3=11
已知x加y等于110,xy等于33,求(2x减3y减2xy)减(x减4y加xy)的值.
已知x加y等于110,xy等于33,求(2x减3y减2xy)减(x减4y加xy)的值.
数学人气:711 ℃时间:2019-12-16 03:49:26
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