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如图在平行四边形ABCD中P是AB边上任意一点,过点P作PE⊥AB,交AD于E,连接CE,CP,已知角A=60°.
如图在平行四边形ABCD中P是AB边上任意一点,过点P作PE⊥AB,交AD于E,连接CE,CP,已知角A=60°.
问答人气:846 ℃时间:2024-05-09 07:13:43
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